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Measurement is the process of assigning numbers to physical quantities. In mathematics, understanding measurement units is essential for accurate calculations and real-life problem-solving.
Key Standard Units in the Ghanaian Context:
| Quantity | Unit | Symbol |
|---|---|---|
| Length | metre | m |
| Mass | kilogram | kg |
| Capacity/Volume | litre | L |
| Time | second, minute, hour | s, min, h |
| Money | Ghana cedi | GHS |
Length
Measures distance between two points.
Conversion: 1 m = 100 cm, 1 km = 1000 m
Example: A classroom is 8 m long and 6 m wide. Find its perimeter and area.
Mass
Measures how heavy an object is.
Conversion: 1 kg = 1000 g
Example: A bag of rice weighs 12.5 kg. How many grams is this? 12.5 × 1000 = 12,500 g
Capacity
Measures the volume of liquid an object can hold.
Conversion: 1 L = 1000 mL
Example: A jug holds 2.5 L of water. How many mL? 2.5 × 1000 = 2500 mL
Time
Measures the duration of events.
Conversions: 1 h = 60 min, 1 min = 60 s
Example: If a lesson starts at 9:15 am and ends at 10:40 am, what is the duration?
10:40 − 9:15 = 1 h 25 min
Money
Ghanaian Cedis (GHS) used in transactions.
Example: If a student pays GHS 7.50 for a book and GHS 5.25 for a pen, total spent = 7.50 + 5.25 = GHS 12.75
Convert 5.8 km to metres.
Solution: 1 km = 1000 m
5.8 × 1000 = 5800 m
A water tank holds 7.2 L. Convert to mL.
Solution: 7.2 × 1000 = 7200 mL
A sugar packet weighs 0.75 kg. Convert to grams.
Solution: 0.75 × 1000 = 750 g
A football match lasted 1 hour 50 minutes. Convert to minutes.
Solution: 1 h = 60 min → 60 + 50 = 110 min
A student has GHS 12.50 and spends GHS 4.25. How much is left?
Solution: 12.50 − 4.25 = GHS 8.25
Geometry is the study of shapes and angles.
Definition: An angle is formed when two lines meet at a point (vertex).
Units: Degrees (°)
Types of Angles:
Acute: < 90°
Right: = 90°
Obtuse: > 90° but < 180°
Straight: = 180°
Reflex: > 180° but < 360°
Formulas
Angles around a point = 360°
Angles on a straight line = 180°
Examples
Angle A = 35°, find its complement.
Solution: Complement = 90 − 35 = 55°
Angle B = 120°, find its supplement.
Solution: Supplement = 180 − 120 = 60°
Two angles on a straight line are 70° and x. Find x.
Solution: 70 + x = 180 → x = 110°
Angles in a triangle sum = 180°. Two angles 50° and 60°, find third.
Solution: 180 − (50 + 60) = 70°
Angles around a point = 360°. Three angles 90°, 120°, x. Find x.
Solution: 90 + 120 + x = 360 → x = 150°
2D Shapes: Triangle, Quadrilateral, Circle, Rectangle, Square, Pentagon, Hexagon
3D Shapes: Cube, Cuboid, Cylinder, Sphere, Cone, Pyramid
Properties
Triangle: 3 sides, sum of angles = 180°
Quadrilateral: 4 sides, sum of angles = 360°
Circle: 360° around center, πr² = area, 2πr = circumference
Definition: Symmetry is when a shape can be divided into identical halves.
Types:
Line (Reflection) Symmetry
Rotational Symmetry
Examples
Square: 4 lines of symmetry, rotational symmetry 90°
Rectangle: 2 lines of symmetry, rotational symmetry 180°
Equilateral Triangle: 3 lines of symmetry
Circle: infinite lines of symmetry
Letter A: 1 vertical line of symmetry
Types by sides: Equilateral, Isosceles, Scalene
Types by angles: Acute, Right, Obtuse
Properties
Sum of interior angles = 180°
Exterior angle = sum of opposite interior angles
Examples
Right triangle with angles 90°, 30°, find third angle.
Solution: 180 − (90 + 30) = 60°
Scalene triangle with sides 5 cm, 7 cm, 8 cm. Perimeter?
Solution: 5 + 7 + 8 = 20 cm
Equilateral triangle side 6 cm. Area?
Solution: Area = (√3/4) × a² = (√3/4) × 36 ≈ 15.59 cm²
Right triangle sides 3 cm, 4 cm, find hypotenuse.
Solution: c² = a² + b² → c² = 9 +16 = 25 → c = 5 cm
Exterior angle 110°, find opposite interior angles.
Solution: 110 = sum of opposite angles
Types: Square, Rectangle, Parallelogram, Trapezium, Rhombus
Properties:
Sum of interior angles = 360°
Opposite sides equal in parallelogram
Diagonals bisect each other in rhombus
Examples
Rectangle 8 m × 5 m, perimeter?
Solution: 2(8 + 5) = 26 m
Rhombus diagonals 6 cm and 8 cm, area?
Solution: Area = (d1 × d2)/2 = (6 × 8)/2 = 24 cm²
Trapezium bases 10 cm, 6 cm, height 4 cm, area?
Solution: Area = ½(h)(b1+b2) = ½(4)(10+6)=32 cm²
Square side 7 cm, area?
Solution: 7 × 7 = 49 cm²
Parallelogram base 12 cm, height 5 cm, area?
Solution: 12 × 5 = 60 cm²
Formulas:
Circumference: C = 2πr or πd
Area: A = πr²
Examples
Circle radius 7 cm, circumference?
Solution: C = 2πr = 2 × 3.1416 × 7 ≈ 43.98 cm
Circle radius 5 cm, area?
Solution: A = πr² = 3.1416 × 25 ≈ 78.54 cm²
Circle diameter 10 cm, circumference?
Solution: C = πd = 3.1416 × 10 ≈ 31.416 cm
Circle radius 3 cm, find diameter.
Solution: d = 2r = 6 cm
Circle area 50.24 cm², find radius.
Solution: A = πr² → r² = 50.24 / 3.1416 ≈ 16 → r = 4 cm
Distance around a 2D shape
Formula examples:
Rectangle: P = 2(l + w)
Square: P = 4 × side
Triangle: P = a + b + c
Examples
Square 6 cm → P = 4 × 6 = 24 cm
Rectangle 5 × 8 → P = 2(5+8) = 26 cm
Triangle 3,4,5 → P = 12 cm
Parallelogram base 7, side 4 → P = 2(7+4) = 22 cm
Trapezium sides 6,8,5,7 → P = 26 cm
Space enclosed in 2D shape
Examples:
Square: A = s²
Rectangle: A = l × w
Triangle: A = ½(b × h)
Trapezium: A = ½(h)(b1 + b2)
Circle: A = πr²
Worked Examples (5)
Rectangle 6 × 9 → A = 54 cm²
Square 5 → 5² = 25 cm²
Triangle base 10, height 6 → ½(10×6)=30 cm²
Trapezium b1=8, b2=6, h=5 → ½(14×5)=35 cm²
Circle r=4 → 3.1416 × 16 ≈ 50.27 cm²
Space occupied by 3D shape
Formulas:
Cube: V = s³
Cuboid: V = l × w × h
Cylinder: V = πr²h
Worked Examples (5)
Cube side 3 cm → V = 3³ = 27 cm³
Cuboid 4 × 5 × 6 → V = 120 cm³
Cylinder r=3, h=7 → V = 3.1416 × 9 × 7 ≈ 197.92 cm³
Cube side 5 → V = 125 cm³
Cylinder r=2, h=10 → V = 3.1416 × 4 × 10 ≈ 125.66 cm³